Hello!,

I'm trying to obtain a random number in batch file.

if I type
in command prompt work ok, but if I put this instruction in batch file, don't
work!

anybody know why?

thanks!

news:797b38778d19c@uwe...
Try doubling the use of %:

http://www.aumha.org/a/batches.php

"NOTE: The %% is necessary because this is in
a batch file which, otherwise, would give a special
meaning to a single %. "

news:797b38778d19c@uwe...

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At a command prompt I get:

nnnnn%108

where nnnnn is a random integer. In a batch file I get:

nnnnnn08

This is because %1 is blank. If I pass "Test" to the batch file as the first
argument, I get an error because "Test" is not numeric. If I pass 23 as the
argument, I get:

nnnnnn2308

Seems to work for me. Of course the environment variable only lasts until I
exit the command prompt.

the solution is written by BSOD in nabble forum:
----------------
BSOD wrote:
Cos in a batch %108 is interpreted as a command line parameter passed to the .
bat, the same as %0 and %1 etc etc.

use this :

SET /A X=%RANDOM%%%108%
---------------

thanks to all!.

bvb47 wrote:

the solution is written by BSOD in nabble forum:
----------------
BSOD wrote:
Cos in a batch %108 is interpreted as a command line parameter passed to the .
bat, the same as %0 and %1 etc etc.

use this :

SET /A X=%RANDOM%%%108%
---------------

thanks to all!.

bvb47 wrote:

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